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(x+1)/(x-11) = x-5 → Find x Substitute y=x-8. Everything shifts: x+1=y+9, x-11=y-3, x-5=y+3. The equation becomes √(y+9)/(y-3) ... (4x-3)/(3x+4)=(x⁵-2)/(1+2x⁵) → Find all values of x Then if you
(4+x)/(2+√(4+x))=√(4-x)/(2-√(4-x)) → Find x Let a=√(4+x) and b=√(4-x).
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- x⁴ = (11x-6)/(6x-11) → Find all values of x
- (3x-9)⁴=81 → Find all four values of x. No substitution. Rewrite 81 as 3⁴. (3x-9)⁴-3⁴=0. First
- Sum
- x=√[(5x²+6x+5)/(x²+6x+9)] → Find x. Two methods. Domain first: x≥0 since the left side is a
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